User blog:Muhammedmco/Busou Renkin - Kazuki drills a hole in a giant

Introduction
Feat in Question.

Calc
Kazuki is 1.75 m.

Going by this scan, he is 130 px compared to the giant.

1.75/130 = 0.01346153846 m/px.

Giant's height = 732 px = 9.853846154 meters.

To calculate his radius, we need to find the arm's width. Unfortunately, we can only see one arm due to the page not showing the other arm, so i will scale it to the visible arm's width.

Giant Arm's width = 100 px = 1.346153846 m.

Giant's width (Without the left arm) = 381 px = 5.128846154 meters.

Giant's width (With the left arm) = 6.475 meters.

Radius = 3.2375 meters.

The giant looks like a cone.

Volume of Giant = 1/3*(22/7)*r^2*h

Plugging it into this:

Volume of Giant = 108.15682991955 m^3

Now, to know the mass of the Giant, since this feat is blatant kinetic energy, i will assume steel, since Koshaku Chouno, who transformed into a Homunoculus, had bullets reflected off him.

Steel's Density = 8050 kg/m^3.

Mass = Volume*Density = 108.15682991955*8050 = 870662.48085238 kg. (Class K)

Kazuki traveled to the Giant's left shoulder. I'm gonna use that for speed.

I will also use this scan as well, because it showed that Kazuki traveled further into the air even after piercing the Giant.

Distance Kazuki flew = 1107 px + 547 px = 1654 px = 22.26538462 meters.

Timeframe = 1/60 = 0.01666666667 seconds.

Speed = 22.26538462/0.01666666667 = 1335.923077 m/s = Mach 3.894819466472 (Supersonic+)

Finally, for the KE.

KE = 1/2*m*V^2 = 1/2*(870662.48085238)*(1335.923077)^2 = 776932000000 Joules = 185.6912045889