User blog:Dragonfriendsomega897/Ridiculous Power of Gran Rey Cero !!!

Gran Rey Cero Calc !!!
We need the size of the Las Noches first.

According to Nel the previous Espada 3 states that it takes 3 Days to walk to the Enterance of the Las Noches. We can lowball this and say that Ichigo and his friends where at the edge of the castle. We get that 1 Side of the Las Noches has a Length of 725.76 Km with a Base with a surface area of 526,727.5776 Square Km. Using this we can scale the size of the Entire Las Noches. We need the Surface Area of Las Noches and the Volume of Las Noches.

Dome
Using this Semi Ellipsoid calculator we can get the Surface Area of the Dome. Bisected axis (a) = 97.635 Km Second semi axis (b) = 94.38 Km Third semi axis (c) = 94.38 Km Total Surface Area of the Dome = 85,243.22933806125 Square Km. https://imgur.com/CZgN4mo We need to take the surface area of the bottom of the Dome since we only require the Surface Area of the Surface of the Las Noches. Surface Area of a Disk = pi x R^2 Surface Area of a Disk = pi x 94.38^2 Surface Area of a Disk = 27,984.0017123 Square Km.

Surface Area of the Surface of the Dome = Total Surface Area of the Dome - Surface Area of a Disk Surface Area of the Surface of the Dome = 85,243.22933806125 - 27,984.0017123 Surface Area of the Surface of the Dome = 57,259.2276258 Square Km.

Small Cuboid
Curved Surface Area of the Small Cuboid = 2 x Height x (Length + Breadth) Curved Surface Area of the Small Cuboid = 2 x 19.5 x (677 + 677) Curved Surface Area of the Small Cuboid = 52,806 Square Km

Now for the Upper Surface Area of Small Cuboid we need to get the Total Surface Area of the Upper Layer of Small Cuboid and then substract the Surface Area of the Disk from it.

Total Surface Area of the Upper Layer = Length x Breadth Total Surface Area of the Upper Layer = 677 x 677 Total Surface Area of the Upper Layer = 458,329 Square Km.

Upper Surface Area of Small Cuboid = Total Surface Area of the Upper Layer of Small Cuboid - Surface Area of the Disk Upper Surface Area of Small Cuboid = 458,329 - 27,984.0017123 Upper Surface Area of Small Cuboid = 430,344.998288 Square Km.

Total Surface Area of the Surface of the Small Cuboid = Curved Surface Area of the Small Cuboid + Upper Surface Area of Small Cuboid Total Surface Area of the Surface of the Small Cuboid = 52,806 + 430,344.998288 Total Surface Area of the Surface of the Small Cuboid = 483,150.998288 Square Km.

Big Cuboid
Curved Surface Area of the Big Cuboid = 2 x Height x (Length + Breadth) Curved Surface Area of the Big Cuboid = 2 x 145 x (725.76 + 725.76) Curved Surface Area of the Big Cuboid = 420,940.8 Square Kilometer.

Now for the Upper Surface Area of Big Cuboid we need to get the Total Surface Area of the Upper Layer of Big Cuboid and then substract the Surface Area of the Small Cuboid's bottomward from it.

Upper Surface Area of Big Cuboid = Total Surface Area of the Upper Layer of Big Cuboid - Surface Area of the Small Cuboid's bottomward Upper Surface Area of Big Cuboid = (725.76 x 725.76) - (677 x 677) Upper Surface Area of Big Cuboid = 526,727.5776 - 458,329 Upper Surface Area of Big Cuboid = 68,398.5776 Square Km

Total Surface Area of the Surface of the Big Cuboid = Curved Surface Area of the Big Cuboid + Upper Surface Area of Big Cuboid Total Surface Area of the Surface of the Big Cuboid = 420,940.8 + 68,398.5776 Total Surface Area of the Surface of the Big Cuboid = 420,940.8 + 68,398.5776 Total Surface Area of the Surface of the Big Cuboid = 489,339.3776 Square Kilometer

Las Noches
Surface Area of Las Noches = Surface Area of the Surface of the Dome + Total Surface Area of the Surface of the Small Cuboid + Total Surface Area of the Surface of the Big Cuboid Surface Area of Las Noches = 57,259.2276258 + 483,150.998288 + 489,339.3776 Surface Area of Las Noches = 1,029,749.60351 Square Kilometer or 1,029,749,603,510 Square Meter.

Using ((Square Root of Surface Area (Km)/0.28)^3)/2 = (Answer in Kilotons) we can get Energy needed to destroy Las Noches. Square root of 1,029,749.60351 = 1014.76578751 ((Square Root of Surface Area (Km)/0.28)^3)/2 = (Answer in Kilotons) '''((1014.76578751/0.28)^3)/2 = 23,800,898,946.2142378 Kilotons of TnT 23,800,898,946.2142378 Kilotons of TnT = 9.95829612e+22 Joules or 23.8 Teratons of TnT or Country Level'''

Dome
Using this Semi Ellipsoid calculator we can get the Volume of the Dome. Bisected axis (a) = 97.635 Km Second semi axis (b) = 94.38 Km Third semi axis (c) = 94.38 Km Volume of the Dome = 1,821,478.671451722 Cubic Km

Small Cuboid
Volume of the Small Cuboid = Length x Breadth x Height Volume of the Small Cuboid = 677 x 677 x 19.5 Volume of the Small Cuboid = 8,937,415.5 Cubic Km

Big Cuboid
Volume of the Big Cuboid = Length x Breadth x Height Volume of the Big Cuboid = 725.76 x 725.76 x 145 Volume of the Big Cuboid = 76,375,498.752 Cubic Km

Volume of Las Noches = 1,821,478.671451722 + 8,937,415.5 + 76,375,498.752 Volume of Las Noches = 87,134,392.9235 Cubic Km or 87,134,392,923,500,000,000,000 Cubic Centimeter

We know Hado's and Cero atleast Pulverize Pulverization: Applied when the matter that was destroyed was turned to dust. We usually use this value when we see no remains of the matter that was destroyed in the aftermath of the attack. Grimmjow's Cero Pulverizing half of Menoly Grimmjow's Cero Pulverizing top half of Luppi Even Hado's in 50s can Incinerate the target according to Bleach Official Character Book 2 MASKED It is even stated that Hado's can destroy stuff to non existence

Cero's like Gran Rey Cero are so powerful that they are forbidden to even use it inside the Las Noches as Gran Rey Cero can destroy Las Noches It is stated that Gran Rey Cero should not be used in Las Noches Ulquiorra is so sure that it can destroy Las Noches that he leaves Las Noches to fight Ichigo Ulquiorra stating that Gran Rey Cero can destroy Las Noches

The value of Pulverization is 214.35 Joules per Cubic Centimeter. The explosions from Gran Rey Cero are Omni-directional, so they form into a sphere and they would able to completetly consume Las Noches and Pulverize it but we will Lowball it and say it will just explode Las Noches. Energy to Destroy Las Noches = Volume of Las Noches (Cubic Centimeter) x 214.35 Joules per Cubic Centimeter Energy to Destroy Las Noches = 87,134,392,923,500,000,000,000 x 214.35 Energy to Destroy Las Noches = 87,134,392,923,500,000,000,000 x 214.35 Energy to Destroy Las Noches = 1.8677257123152225e+25 Joules of Energy or 4.464 Petatons of TnT or Low Multi-Continent level.